Question

y= x sin inverse x/√1-x square. find dy/dx​

Answer 1

Answer:

dy/dx=1/√1-x^2/(1-x)^2

=1/√1-x^2/1+x^2-2x

=1/√1+x^2-2x-x^2/(1+x)^2

=1/√1-2x/(1+x)^2

hope it helps you