Question

Y= x sin x^2 then the value of dy/dx

Answer 1

Answer:

sinx^2 + x(2sinx) cosx

Answer 2

Answer:

2x²cos(x)²+ sin(x)²

Explanation:

Given ,

y = x.sinx²

$\frac{dy}{dx} \\ \\ = \frac{d ( x \times { \sin } {x}^{2} )}{dx} \\ \\ = x \times \frac{d \sin {x}^{2} }{dy} + \sin {x}^{2} \times \frac{dx}{dx} \\ \\ = x \times \cos {x}^{2} \times 2x + \sin {x}^{2} \\ \\ = 2 {x}^{2} \cos {x}^{2} + \sin{x}^{2}$