y = x^sin^x find dy/dx
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it will be done by chain rule
sin^x x^(sin^x-1)×2sinxcosx
so
sin^x x^(sin^x-1)sin2x
sin^x x^(sin^x-1)×2sinxcosx
so
sin^x x^(sin^x-1)sin2x
Anonymous:
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