Question

y=x^sin^x find Dy/dx
​

Answer 1

Answer:

y=x

sinx

logy=sinxlogx

dx

d

(logy)=

dx

d

(sinxlogx)

y

1

dx

dy

=sinx×

dx

d

(logx)+logx

dx

d

(sinx)

y

1

dx

dy

=sinx×

x

1

+logxsinx

dx

dy

=y(

x

sinx

+logxsinx)

∴

dx

dy

=x

sinx

(

x

sinx

+logxsinx)

Step-by-step explanation:

Hope it is helpful