Question

y+x = sin(y+x) find dy/dx ??​

Answer 1

y+x = sin(x+y)

Differentiating both sides with respect to x

dy/dx + 1 = cos(x+y)(1+dy/dx).....(applying chain function rule here)
(1+dy/dx){cos(x+y)-1)=0
So,
dy/dx = -1
and cos(x+y) = 1

Answer 2

Answer:

This is an trigonometric function which is in the form of u.v.

So to differentiate this function, you need to know the differentiation of u.v function.

Thus, d/dx(u.v)=u.dv/dx+v.du/dx.d/dx(u.v)=u.dv/dx+v.du/dx.