Question

Y= [ x+(√x+1 )],find dy÷dx .

Answer 1

Answer:

\frac{dy}{dx} = 1+1/2(x+1)^-1/2

Step-by-step explanation:

dy/dx = d/dx(x+(√x+1)

= 1 + 1/2 (x+1)^1/2-1

\frac{dy}{dx} = 1+1/2(x+1)^-1/2