y=x^√x then dy/dx=? please answer fast someone
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first take log both the sides
the the ealquation is logy= √xlogx
the apply product rule which will give you
1/y dy/dx=1/2√x×logx +1/x√x
the take LCM on RHS and bring y to rhs and substitute it with value given in the question
the the ealquation is logy= √xlogx
the apply product rule which will give you
1/y dy/dx=1/2√x×logx +1/x√x
the take LCM on RHS and bring y to rhs and substitute it with value given in the question
Hareh131101:
sorry the rule i used is x^n dx = nx^n-1
ans is x^√x(2+logx)/2√x
Now its correct you can see why it's like that
thank you for providing such aquestion i was mistaken at first as i haven't seen the topic thoroughly since many days
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