y=√x+y then prove that dy/dx=1/2y-1
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Answer:
dy/dx = 1/(2y -1)
Step-by-step explanation:
y=√x+y then prove that dy/dx=1/2y-1
y=√x+y
Squaring both sides
y² = x + y
2y(dy/dx) = 1 + dy/dx
=> dy/dx(2y -1) = 1
=> dy/dx = 1/(2y -1)
QED
Hence Proved
dy/dx = 1/(2y -1)
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