Question

y = √ x2 + 5 slove it​

Answer 1

$\huge \bold \color{red} {\mathfrak {\underbrace {\overbrace \green{answer}}}}$

$\bold{we \: have \: y = \sqrt{ {x}^{2} } + 5} \\ differentiate \: w.r.t.x \\ = > \frac{dx}{dy} = \frac{d}{dx} ( \sqrt{ {x}^{2} } + 5) \\ (now \: consider \: {x}^{2} + 5 \: \\ and \: by \: using \: the \: formula \: of \: \\ derivative \: of \: \sqrt{u} ) \\ = > \frac{dx}{dy} = \frac{1}{2 \sqrt{ {x}^{2} } + 5 } . \frac{dx}{dy} ( {x}^{2} + 5) \\ = > \frac{dx}{dy} = \frac{1}{2 \sqrt{ {x}^{2} + 5} } (2x) \\ = > \frac{dx}{dy} = \frac{1}{ \sqrt{ {x}^{2} + 5} }$

Answer 2

Answer:

differentiatew.r.t.x

=>

dy

dx

=

dx

d

(

x

2

+5)

(nowconsiderx

2

+5

andbyusingtheformulaof

derivativeof

u

)

=>

dy

dx

=

2

x

2

+5

1

.

dy

dx

(x

2

+5)

=>

dy

dx

=

2

x

2

+5

1

(2x)

=>

dy

dx

=

x

2

+5

1

Step-by-step explanation:

mark as brainlist