y=(x²+5x)logx find dy/dx
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Answer:
Step-by-step explanation:
y = (x² + 5x) logx
dy/dx = d/dx [ (x² + 5x) logx]
= (x² + 5x) * d/dx(logx) + logx * d/dx (x² + 5x)
= (x² + 5x ) * 1/x + logx (2x + 5)
= (x + 5) + (2x + 5) logx.
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