Question

y=x²-cosx then dy/dx is​

Answer 1

Answer:

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y=x²-cosx

y=x²-cosxdy/ dx = d( x²- cos x)/dx

y=x²-cosxdy/ dx = d( x²- cos x)/dx = d( x² )/dx - d( cos x)/ dx

y=x²-cosxdy/ dx = d( x²- cos x)/dx = d( x² )/dx - d( cos x)/ dx

y=x²-cosxdy/ dx = d( x²- cos x)/dx = d( x² )/dx - d( cos x)/ dx = 2x - (- sin x )

y=x²-cosxdy/ dx = d( x²- cos x)/dx = d( x² )/dx - d( cos x)/ dx = 2x - (- sin x ) = 2x + sin x

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