Question

y x² + Kx+6= (x+2) (x+3)
then value of k is​

Answer 1

Answer:

Let's solve for k.

yx2+kx+6=(x+2)(x+3)

Step 1: Add -x^2y to both sides.

x2y+kx+6+−x2y=x2+5x+6+−x2y

kx+6=−x2y+x2+5x+6

Step 2: Add -6 to both sides.

kx+6+−6=−x2y+x2+5x+6+−6

kx=−x2y+x2+5x

Step 3: Divide both sides by x.

kx/x=−x2y+x2+5x/x

k=−xy+x+5

Answer 2

Step-by-step explanation:

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