Math, asked by harshaharshi2002, 5 months ago

y=x²/logx find dy/dx

Answers

Answered by rajputboy072

0

dy/dx= 2xlogx-x/2logx

Attachments:

Answered by SAMZUKO

0

Step-by-step explanation:

use chain rule

d(u/v)/DX = udv-vdu/v^2

after solving 2xlogx-x/(logx)^2

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