Question

y=x² sin⁴x+cos-²x differentiate by product rules
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Answer 1

Step-by-step explanation:

$Given </p><p></p><p></p><p>y=x2sinx</p><p></p><p></p><p>Using</p><p></p><p>dxd(u .v)=vdxdu+udxdv</p><p></p><p></p><p>Differentiating on both sides</p><p></p><p></p><p>⟹dxdy=dxd(x2sinx)</p><p></p><p></p><p>⟹dxdy=sinxdxd(x2)+x2dxd(sinx)</p><p></p><p></p><p>⟹dxdy=2xsinx+x2cosx</p><p></p><p>$