Question

y=x2 √x +x4log x w. r. t. x
​

Answer 1

Answer:

y=

x

2

+4x−7

[

x

=

2

x

1

Differentiating w.r.t. x, we get

dx

dy

=

2

x

2

+4x−7

1

⋅

dx

d

(x

2

+4x−7)

=

2

x

2

+4x−7

1

(

dx

d

x

3

+

dx

d

4x−

dx

d

7)

=

2

x

2

+4x−7

1

⋅(2x+1−0)

=

2

x

2

+4x−7

2(x+2)

=

x

2

+4x−7

(x+2)

Step-by-step explanation:

y=

x

2

+4x−7

[

x

=

2

x

1

Differentiating w.r.t. x, we get

dx

dy

=

2

x

2

+4x−7

1

⋅

dx

d

(x

2

+4x−7)

=

2

x

2

+4x−7

1

(

dx

d

x

3

+

dx

d

4x−

dx

d

7)

=

2

x

2

+4x−7

1

⋅(2x+1−0)

=

2

x

2

+4x−7

2(x+2)

=

x

2

+4x−7

(x+2)