Question

y=xlogx:dy/dx?explain

Answer 1

HEYA,

HERE IS YOUR ANSWER,

=> y = x * log(x)

=> dy/dx = 1 * log(x) + x * (1/x)

=> log(x) + 1  (ANS).

HOPE IT HELPS YOU,
THANK YOU.

Answer 2

Hi ,

y = xlogx

dy/dx = x ( log x )' + log x ( x )'

= x × 1/x + log x × 1

= 1 + log x

I hope this helps you.

: )