y=xsin(1/x) dy/dx find
chaharsandeep721:
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Answer:
y=1−x2xsin−1x
y1−x2=xsin−1x
Differentiating both sides w.r.to x, we get
y⋅21−x2(−2x)+1−x2dxdy=x⋅1−x21+sin−1x
−xy+(1−x2)dxdy=x+1−x2sin−1x
−xy+(1−x2)dxdy=x+1−x2⋅xy1−x2
−xy+(1−x2)dxdy=x+xy(1−x2)
−xy+(1−x2)dxdy=x+xy−yx
(1−x2)dxdy=x+xy
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Step-by-step explanation:
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