(y – xy2) dx - (x + x2y) dy = 0
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It is of the form
M dx + N dy = 0
M= y — x y^2 , N = x — x^2 y
Partial derivative of M w.r.t. ‘y' = 1 — 2xy
Partial derivative of N w.r.t. ‘x' = 1 — 2xy
Since these partial derivatives are equal, hence it's an exact differential equation.
It's solution is obtained by integrating all the terms of M w.r.t. ‘x' taking ‘y' as a constant and integrating only those terms of N w.r.t. ‘y' in which ‘x' is absent and then equating the sum to a constant.
Hence the solution is
xy — (1/2) x^2 y^2 = C
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