y(y-1)=(y+3)( y+1) find the value of y
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Answer:
y²-y = y²+y+3y+3
y²-y = y²+4y+3
y²-y² = 4y-y+3
0 = 3y + 3
-3 = 3y
y = -3/3
y= -1
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