y^y=sinx calculate dy/dx
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y^y=sinx
logy^y=logsinx
ylogy=logsinx
y( 1/y)+logy dy/dx=(1/sinx) cosx
1+logy dy/dx=cotx
logy dy/dx=cotx-1
dy/dx=(cotx-1)/logy ans
logy^y=logsinx
ylogy=logsinx
y( 1/y)+logy dy/dx=(1/sinx) cosx
1+logy dy/dx=cotx
logy dy/dx=cotx-1
dy/dx=(cotx-1)/logy ans
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