Question

(y+z)1/3+(z+x)1/3+(x+y)1/3=0 then (x+y+z)3=27(x3+y3+z3)​

Answer 1

Answer:

Step-by-step explanation:

(y+z)/3 + (z + x)/3 + (x + y)/3 = 0

(y + z + z + x + x + y)/3 = 0

2x + 2y + 2z = 0

2(x + y + z) = 0

x + y + z = 0

(x + y + z)³ = 27(x³ + y³ + z³)

(0)³ = 27(x³ + y³ + z³)

0 = x³ + y³ + z³

hope this helps ☺️