y,z,10x,8x find the value of xyz
Answers
Answered by
4
Step-by-step explanation:
To make sure that x, y and z are more than Zero
X must be less than 10 (So X is from 1 to 9.9) so if we only accept the 0.1 differences (Becasue I am talking in business) it is only 90 chance to have value of X
X = 6.4
y = 9.6
z = 84
Answered by
0
Answer:
∠PQR+ext.∠Q=180
∘
[Linear pair]
∠PQR+80
∘
=180
∘
⇒∠PQR=100
∘
x+100
∘
=180
∘
[Supplementary angles of parallelogram]
x=80
∘
In △PSR,Z=∠SRP [Alternate angles]
∴80
∘
+60
∘
+Z=180
∘
⇒Z=180
∘
−140
∘
=40
∘
In △PQR,
40
∘
+y+100
∘
=80
∘
y=180
∘
−140
∘
=40
∘
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