Question

((y-z)p+(z-x)q)=x-y solve​

Answer 1

Answer:ϕ(x+y+z,x2+y2+z2)=0

Step-by-step explanation:

y−z)p+(z−x)q=x−y  

This is Lagrange's linear equation Pp+Qq=R

∴ The auxiliary equation is

dxy−z=dyz−x=dzx−y

Each is equal to dx+dy+dzy−z+z−x+x−y

=d(x+y+z)0

⇒d(x+y+z)=0

∴ On Integration, x+y+z=a

Also, each ratio is equal to

xdx+ydy+zdzx(y−z)+y(z−y)+z(x−y)

=12d(x2+y2+z2)0

⇒d(x2+y2+z2)=0

Integrating, x2+y2+z2=b

∴ The general solution is

ϕ(x+y+z,x2+y2+z2)=0

Answer 2

Answer:

Step-by-step explanation: