Question

(y+z)p+(z+x)q=x+y solve this question
​

Answer 1

$\huge{ \red{ \underline{ \overline{ \mid{ \bold{ \purple{ \: \: SOLUTION \: \: \red{ \mid}}}}}}}}$


$\bold{(y + z)p \: + \: (z + x) \: q = x + y} \\ \\ \bold{ \Longrightarrow \: yp + zp + zq + xq = x + y} \\ \\ \bold{ \Longrightarrow \: xp - x + yp - y + zp + zq = 0} \\ \\ \bold{ \Longrightarrow \: x(p - 1) + y(p - 1) + z( p - q) = 0} \\ \\ \bold{ \Longrightarrow \: ( p - 1)(x + y) + z( p - q) = 0}$

Answer 2

$\huge{ \red{ \underline{ \overline{ \mid{ \bold{ \purple{ \: \: SOLUTION \: \: \red{ \mid}}}}}}}}$

$\begin{lgathered}\bold{(y + z)p \: + \: (z + x) \: q = x + y} \\ \\ \bold{ \Longrightarrow \: yp + zp + zq + xq = x + y} \\ \\ \bold{ \Longrightarrow \: xp - x + yp - y + zp + zq = 0} \\ \\ \bold{ \Longrightarrow \: x(p - 1) + y(p - 1) + z( p - q) = 0} \\ \\ \bold{ \Longrightarrow \: ( p - 1)(x + y) + z( p - q) = 0}\end{lgathered}$