Y+z-x=k,(z+x-y)(x+y-z) is proportional to yz then prove that x+y+z is proportional to yz
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Proof:
Given, y + z - x = k ..... (1)
Also (z + x - y) (x + y - z) ∝ yz
or, (z + x - y) (x + y - z) = cyz ,
where c is proportional constant
or, xz + yz - z² + x² + xy - xz - xy - y² + yz = cyz
or, x² - y² - z² + 2yz = cyz
or, x² - (y² + 2yz + z²) = cyz - 2yz - 2yz
or, x² - (y + z)² = (c - 4) yz
or, (x - y - z) (x + y + z) = (c - 4) yz
or, {- (y + z - x)} (x + y + z) = (c - 4) yz
or, - k (x + y + z) = (c - 4) yz, by (1)
or, x + y + z = (4 - c)/k * yz
Since (4 - c)/k is a constant value, we can write
x + y + z ∝ yz
Hence, proved.
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