Question

y²+1/3y=2 pls solve this​ quadratic equation solve using formulaplz fast ​

Answer 1

$\mathfrak{AnSwEr}$

Given quadratic equation = $\sf{\frac{y^{2} + 1}{3y} = 2}$

Equation becomes = $\sf{y^{2} - 6y + 1 = 0}$

The Quadratic Formula = $\sf{\frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}}$

Here, a = 1, b = (-6), c = 1

Substitute the values and find the answer.

Answer :- $\sf{3 \pm 2\sqrt{2}}$