Math, asked by hrishikeshjadhav03, 9 months ago

y²+1/y =2 how to solve and say that its a quadratic equation

Answers

Answered by SilverShades67
1

+1/y= 2

+1/y= 2

+1 = 2y

-2y+1= 0

+y+y+1= 0

y(+1)+1(y+1)=0

(y+1)(+1)= 0

y= -1 , 1

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Answered by xicacim193
1

Answer:

(y^2+1)/y = 2

so (y^2 + 1) = 2y

so y^2 - 2y + 1 = 0

so y^2 - y - y + 1 = 0

y(y - 1) - 1(y - 1) = 0

(y-1)(y-1) = 0

Therefore y - 1 = 0

so y = 1

Since degree of this equation is 2, thus we can say it is quadratic equation

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