Math, asked by tenzinsherpa763, 1 month ago

y2+10y+16
y2 + 10y + 16

Answers

Answered by TigerMan28
2

Answer:

(y + 2)(y + 8)

Step-by-step explanation:

y^2 + 10y + 16

= y^2 + 2y + 8y + 16

= y(y+2) + 8(y + 2)

= (y+2)(y+8)

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Answered by TheMoonlìghtPhoenix
11

Step-by-step explanation:

In this question, we need to factorise the following expression:-

\tt{y^2 + 10y + 16}

We will apply Middle term Factorisation for this :-

\tt{y^2 + 10y + 16}

Step 1 :- Calculating the factor

We need to calculate the factor first :-

\tt{ax^2 + by + c }

  • Let us consider this sample. So, we will multiply a with c.

\tt{y^2 + 10y + 16}

  • Multiplying 1×16 = 16

Step 2 :- Breaking the Middle Term :-

We know that :-

  • We will now break \tt{by's \ b} into \tt{b_1 \ and \ b_2} respectively.

  • 8×2 = 16, and 8+2= 10,

so, we will break it in 8y + 2y

Step 3 :- Factorise :-

\tt{y^2 + 10y + 16}

\tt{y^2 + 8y + 2y +  16}

\tt{y(y + 8) + 2(y+  16)}

\tt{(y + 8) (y +2) } is the required solution.

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