Question

(y² - 10y + 21) ÷ (y - 3)
please help me... and also with explaination

Answer 1

Answer:

(y-7)

Step-by-step explanation:

The dividend can be written as

y²-7y-3y+21

=(y-3)(y-7)

Therefore, (y-3)(y-7)/y-3 = y-7

Answer 2

Answer:

(y - 7)

Step-by-step explanation:

Given,

(y² - 10y + 21) ÷ (y - 3);

Here (y² - 10y + 21) is the dividend and (y - 3) is the divisor.

So, the first variable or the numerical of the questiont should be that, that's divide y ^2 completely. (i.e : y)[y(y - 3) = y^2 - 3y]

So, on subtracting (y^2 - 3y) from (y ^ 2 - 10y),

We get -7y +21 [21 borrowed down as per the division rules].

Now,

the first variable or the numerical of the questiont should be that, that's divide (-7y +21) completely.(i.e : -7)[-7(y - 3) = -7y + 21y].

So, after subtracting (-7y +21) from (-7y +21) we get the remainder as 0.

So, our final questiont as answer is (y - 7).