Question

Y²+10y+29=0. solve the quadratic equation

Answer 1

Answer:

The answer for the question is imaginary

Step-by-step explanation:

Since,

We know that in an equation of ax^2+bx+c=0

By P= b^2-4ac,

When P>0 it have real roots

WhenP=0 have real and equal roots

When P<0 it have imaginary roots

So in the given equation,

a=1,b=10,c=29. Then b^2-4ac is equal to 100-116=-16

So this equal if solved wont get a real value