Question

Y2+12y +35 at middle term splitting

Answer 1

This attachment is required answer.

Answer 2

Answer:

The correct answer is $(y+5)(y+7)$.

Step-by-step explanation:

Given:

$y^{2}+12 y+35$

To find  $y^{2}+12 y+35$ the middle term by splitting.

Steps 1

when you break a digit down into smaller digits that, multiplied together, show you that actual number. When you broke a digit into its factors or divisors, that's factorization.

Let, $y^{2}+12 y+35$

Break the expression into groups

$y^{2}+12 y+35$ $=\left(y^{2}+5 y\right)+(7 y+35)$

Step 2

Factor out $y$ from, $y^{2}+5 y$  

$\quad y(y+5)$

Factor out $7$ from $7 y+35$

$: 7(y+5)$

Then,

$\left(y^{2}+5 y\right)+(7 y+35)$ $=y(y+5)+7(y+5)$

Step 3

Factor out the common term $y+5$

$=(y+5)(y+7)$

Therefore, we get

$y^{2}+12 y+35$ $=(y+5)(y+7)$.

#SPJ3