y2+1upon y=2 is it quadratic equation
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Your question needs a correction :
Correct equation : (y² +1)/y = 2
Solution :
By quadratic equation,
a= 1
b = -2
c = 1
Discriminant = b^2 - 4ac
=> (-2)² - 4(1)(1)
=> 4 - 4
=> 0
quadratic equation = {-b±√discriminant} ÷ 2a
x = { - (-2)±√0} ÷ 2(1)
x = 2/2 or 2/2
x = 1
Correct equation : (y² +1)/y = 2
Solution :
By quadratic equation,
a= 1
b = -2
c = 1
Discriminant = b^2 - 4ac
=> (-2)² - 4(1)(1)
=> 4 - 4
=> 0
quadratic equation = {-b±√discriminant} ÷ 2a
x = { - (-2)±√0} ÷ 2(1)
x = 2/2 or 2/2
x = 1
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