Question

y2+1upon y=2 is it quadratic equation

Answer 1

Your question needs a correction :

Correct equation : (y² +1)/y = 2

Solution :

$\frac{ {y}^{2} + 1}{y} = 2 \\ \\ \\ {y }^{2} + 1 = 2y \\ \\ \\ {y}^{2} - 2 y + 1 = 0$

By quadratic equation,

a= 1
b = -2
c = 1

Discriminant = b^2 - 4ac

=> (-2)² - 4(1)(1)
=> 4 - 4
=> 0



quadratic equation = {-b±√discriminant} ÷ 2a


x = { - (-2)±√0} ÷ 2(1)

x = 2/2 or 2/2

x = 1