Math, asked by neha600, 1 year ago

y²+2√3y+3=0 by factorsation method

Answers

Answered by digi18
14

y {}^{2}  + 2 \sqrt{3} y + 3 = 0

y {}^{2}  +  \sqrt{3} y  + \sqrt{3} y + 3 = 0

y(y +  \sqrt{3} ) +  \sqrt{3} (y +  \sqrt{3} ) = 0

(y +  \sqrt{3} )(y  + \sqrt{3} ) = 0

y =  -  \sqrt{3}  \:  \:  \: and -  \sqrt{3}



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Answered by abhi569
21
y² + 2√3y + 3 = 0

=> y² + (√3 + √3)y + 3 = 0

=> y² + √3y + √3y + 3 =0

=> y(y +√3) + √3(y + √3) = 0

=> (y + √3)(y+√3) =0

By zero product rule,

y = -√3


I hope this will help you


-by ABHAY

abhi569: Thanks for choosing a brainlist answer
abhi569: (-;
neha600: my pleasure
abhi569: Hmm
neha600: hmm
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