y²+2√3y+3=0 by factorsation method
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neha600:
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y² + 2√3y + 3 = 0
=> y² + (√3 + √3)y + 3 = 0
=> y² + √3y + √3y + 3 =0
=> y(y +√3) + √3(y + √3) = 0
=> (y + √3)(y+√3) =0
By zero product rule,
y = -√3
I hope this will help you
-by ABHAY
=> y² + (√3 + √3)y + 3 = 0
=> y² + √3y + √3y + 3 =0
=> y(y +√3) + √3(y + √3) = 0
=> (y + √3)(y+√3) =0
By zero product rule,
y = -√3
I hope this will help you
-by ABHAY
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