Question

y²-20y +112= 0. plzzzz help
​

Answer 1

Answer:y2-20y+112=0

Two solutions were found :

y =(20-√-48)/2=10-2i√ 3 = 10.0000-3.4641i

y =(20+√-48)/2=10+2i√ 3 = 10.0000+3.4641i

Step-by-step explanation:

Answer 2

Answer:

${y}^{2} - 20y + 112 = 0 \\ = > {y }^{2} - 20y = 0 - 112 = - 112 \\ = > {y}^{2} - y = - 112 \div 20 = 5.6 \:$