y2 + 3 root 5 divided by 2 * y-5 factorise it
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Secondary School Math 5 points
Solve the following with factorisation method y^2+3/2root5y-5
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ShivanshAggarwal Ambitious
y^2 + 3√5/2y -5
By Middle Term Splitting
y^2 + 4√5/2y - √5/2y - 5
Taking LCM
2y^2 + 4√5y -√5y -10 = 0 (Taking Denominator to RHS)
2y(Y +2√5) -√5(Y +2√5) =0
(Y + 2√5)(2y - √5) = 0
Two cases can be formed
If Y +2√5 = 0
Y = -2√5
If 2y - √5 = 0
Y = √5/2
Hope this answer will help you.
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