y2+3rt(5/2)y-5 answer this plss
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Answered by
1
Answer:
y²+3/2√5y-5=0
Splitting the middle term
y²+4/2√5y-√5/2y-5=0
Taking LCM
2y²+4√5y-√5y-10=0 (Denominator taken to RHS)
2y(y+2√5)-√5(y+2√5)=0
(2y-√5)(y+2√5)=0
∴y= √5/2 or -2√5
Step-by-step explanation:
Answered by
0
Answer:
y^2+3rt(5/2)y-5
=y^2+15/2rty-5
Step-by-step explanation:
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