y²+3y+y+3 when divided by y+1 gives
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Answer:
y+3
y
2
+3y+y+3
y
2
+3y+y+3
=y(y+3)+1(y+3)
=(y+3)(y+1)
y+3
y
2
+3y+y+3
=
(y+3)
(y+3)(y+1)
=(y+1)
Answered by
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