Question

y²+4=3y-1 quadratic equation​

Answer 1

Answer:

Given equation: ${y}^{2}-{3y}+3={0}$

Do to solve quadratic equation..

it's discriminant is negative so the answer doen not exist!!

Answer 2

${y}^{2} + 4 = 3y - 1$

${y}^{2} + 4 - 3y + 1 = 0$

${y}^{2} - 3y + 5 = 0$

${y}^{2} - 3y + 5 = 0$