Question

y2=4ax orthognal trajectory

Answer 1

Answer:

x=0

y=0

Step-by-step explanation:

y²=4ax

y²- 4ax = 0

y²-x=$\frac{0}{4a}$

y²-x=0

y²= x

y = √x

y- √x=0

y-x=√0

y-x=0-(i)

y=x

if x=y

then from 1

y-x=0

we can write

y-y=0

y=0

if y is 0

then x=0 (Because x=y)

Or

y²=4ax

By Discrimaniation method

D=b²-4ac

D=0

0=y²-4ax

y²-x= $\frac{0}{4a}$

y²-x=0

y = √x

y- √x=0

y-x=√0

y-x=0-(i)

y=x

if x=y

then from 1

y-x=0

we can write

y-y=0

y=0

if y is 0

then x=0 (Because x=y)