Question

Y² = 4x, x² = 4y find angle between two curves​

Answer 1

Answer:

Step-by-step explanation:

Y^2=4X, X^2=4Y

2YDY/DX=4 , 2X=4DY/DX

dy/dx=2/y  , dy/dx=x/2

x^2=4√4x

x^2=8√x

x=16√2, then y=√(4*16√2)

y=16

dy/dx=2/16=1/8 ,dy/dx=8√2

tanФ=2/16+8√2/1-2/16*8√2