Question

y2+4y+3 solve this qùestion​

Answer 1

Question :

$y^2 + 4y + 3$

Solve this question.

$\huge\underline\green {\tt Solution:}$

$y^2 + 4y + 3$

= $y^2 + ( 3 + 1 ) y + 3$

= $y^2 + 3y + 1y + 3$

= $y ( y + 3 ) + 1 ( y + 3 )$

= ( y + 1 ) ( y + 3 )

So,

Y = - 1 or Y = - 3

Answer 2

Given:

$\sf y^2+4y+3=0$

To find:

The values of y

Explanation:

Let us first find the dicriminant to know whether it has real roots or not

$\boxed{\sf D=b^2-4ac}$

$\sf for \: y^2+4y+3=0$

$\bullet \sf a=1 \\ \\ \bullet \sf b=4 \\ \\ \bullet \sf c=3$

$\longrightarrow \sf D=4^2-4(1)(3)$

$\longrightarrow \sf D=16-12$

$\longrightarrow \sf D=4>0$

Therefore,it has real roots

$\sf y^2+4y+3=0$

splitting the middle term

$\longrightarrow \sf y^2+3y+y+3=0$

$\longrightarrow \sf y(y+3)+1(y+3)=0$

$\sf (y+3)=0 \\ \boxed{\sf y=-3}$

$\sf (y+1)=0 \\ \boxed{\sf y=-1}$

Extra information:

If D <0

The roots can be found by the formula

$\bullet \sf x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$