y²-8y+16=0 BY FACTORSATION METHOD
Answers
Answered by
11
Hi friend!!
Given, y²-8y+16=0
→y²-4y-4y+16=0
→y(y-4)-4(y-4)=0
(y-4)²=0
y=4
I hope this will help u ;)
Given, y²-8y+16=0
→y²-4y-4y+16=0
→y(y-4)-4(y-4)=0
(y-4)²=0
y=4
I hope this will help u ;)
neha600:
thank you
u are welcome ^_^
my pleasure
Answered by
10
y² - 8y + 16 = 0
y² - (4+4)y + 16 = 0
y² - 4y - 4y + 16 = 0
y(y - 4) -4 (y - 4) =0
(y - 4)(y - 4) = 0
By zero product rule,
y = 4
I hope this will help you
-by ABHAY
y² - (4+4)y + 16 = 0
y² - 4y - 4y + 16 = 0
y(y - 4) -4 (y - 4) =0
(y - 4)(y - 4) = 0
By zero product rule,
y = 4
I hope this will help you
-by ABHAY
(-:
thank you
Welcome, thanks for choosing a brainlist answer
my pleasure
(-:
hmm
Similar questions