Math, asked by rajbhise1, 1 year ago

y2+8y+16=0 y is y square root

Answers

Answered by Anonymous
2
Hey !!

Here is your answer !

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y is y square root ??
Excluding it !

y2 + 8y + 16 = 0
y2 + 4y + 4y + 16 = 0
y ( y + 4 ) + 4 ( y + 4 ) = 0
(y + 4 ) (y + 4) = 0
y = -4 and again y = -4

rajbhise1: hi I need more question answer can you give me all answer
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Answered by TheLifeRacer
2
Hey !!!

y² + 8y + 16 = 0

y² + 4y + 4y + 16 =0 (using spliting method )

y(y+4) + 4(y+4) =0

(y+4)(y+4) = 0

y+4 = 0

y = -4

and again y+4 = 0

y = -4

here value of roots is same so root is real and equal ...

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Hope it helps you !!

@Rajukumar111

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rajbhise1: I have more question please
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