y2+8y+16=0 y is y square root
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Answered by
2
Hey !!
Here is your answer !
__________________
y is y square root ??
Excluding it !
y2 + 8y + 16 = 0
y2 + 4y + 4y + 16 = 0
y ( y + 4 ) + 4 ( y + 4 ) = 0
(y + 4 ) (y + 4) = 0
y = -4 and again y = -4
Here is your answer !
__________________
y is y square root ??
Excluding it !
y2 + 8y + 16 = 0
y2 + 4y + 4y + 16 = 0
y ( y + 4 ) + 4 ( y + 4 ) = 0
(y + 4 ) (y + 4) = 0
y = -4 and again y = -4
rajbhise1:
hi I need more question answer can you give me all answer
Answered by
2
Hey !!!
y² + 8y + 16 = 0
y² + 4y + 4y + 16 =0 (using spliting method )
y(y+4) + 4(y+4) =0
(y+4)(y+4) = 0
y+4 = 0
y = -4
and again y+4 = 0
y = -4
here value of roots is same so root is real and equal ...
#######################
Hope it helps you !!
@Rajukumar111
y² + 8y + 16 = 0
y² + 4y + 4y + 16 =0 (using spliting method )
y(y+4) + 4(y+4) =0
(y+4)(y+4) = 0
y+4 = 0
y = -4
and again y+4 = 0
y = -4
here value of roots is same so root is real and equal ...
#######################
Hope it helps you !!
@Rajukumar111
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