Question

y²-8y+7

please telllll anyone ​

Answer 1

Answer:

y=1 or 7

Step-by-step explanation:

on factorization

y²-8y+7=0

y²-7y-y+7=0

y(y-7)-1(y-7)=0

(y-1)(y-7)=0

hence     y=1   or    7

hope this helps you

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Answer 2

Answer:

${y}^{2} - 8y + 7 = 0 \\ {y}^{2} - 7y - 1y + 7 = 0 \\ y(y - 7) - 1(y - 7) = 0 \\ (y - 1) = 0 \: \: \: or \: (y - 7) = 0 \\ y = 1 \: \: \: \: \: \ \: or \: \: \: \: \: y = 7$