Question

Y²=X³/4-x (2,-2) find the equation of the tangent​

Answer 1

Answer:

Answer

We have,

y

2

−2x

3

−4x+8=0

On differentiation and we get,

2y

dx

dy

−6x

2

−4+0=0

dx

dy

=

2

6x

2

+4

dx

dy

=3x

2

+2

Slope at the point (1,2)

Then,

(

dx

dy

)

(1,2)

=3(1)

2

+2

(

dx

dy

)

(1,2)

=5

Then,

Equation of tangent is

y−y

1

=

dx

dy

(x−x

1

)

⇒y−2=5(x−1)

⇒y−2=5x−5

⇒y−5x+3=0

Hence, this is the answer.