Math, asked by aryansingh82910612, 6 months ago

y2+y-132 please send answer ​

Answers

Answered by Anonymous
5

given, y²+y-132 = 0

y²+12y-11y-132 = 0

y(y+12) - 11(y+12) = 0

(y-11)(y+12) = 0

y-11 = 0 or y+12 = 0

y=11 or y = -12

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