Question

y² - (y+2) (y + 3) /7y+1 =2/3 linear equation


please solve it..
answer=-20/29​

Answer 1

${y}^{2} - \frac{(y + 2)(y + 3)}{(7y + 1)} = \frac{2}{3} \\after \: simplifcation \\ 7 {y}^{3} - 5y - 6 = \frac{2}{3} (7y + 1) \\ 21 {y}^{3} - 15y - 18 = 14y + 2 \\ 21 {y}^{3} - 29y - 20 = 0 \\ after \: further \: simplification \: \\ y = 1.4306$

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