Question

y²-y-(2k+2),when y=-4 .find k​

Answer 1

Hello mate.....

given......

$y {}^{2} - y - (2k + 2) = 0 \\ \\ and \: \: \: \: y = - 4 \: \: ......sub \: this \: \: value \: in \: given \: eqn. \\ \\ ( - 4) {}^{2} - ( - 4) - (2k + 2) = 0 \\ \\ 16 + 4 - 2k - 2 = 0 \\ \\ - 2k + 20 - 2 = 0 \\ \\ - 2k + 18 = 0 \\ \\ 2k = 18 \\ \\ k = 9$

Hope it helps u......

♧◇◇♧....!!!

Answer 2

Answer:

9

Step-by-step explanation:

(-4)^2 - (-4) - (2k + 2) = 0

16 + 4 - 2k - 2 = 0

18 - 2k = 0

-2k = -18

k = -18/-2

k = 9

Hope you find it helpful