Math, asked by mounikspradhans, 6 months ago

Y² +yz +z²/ (x-y)(x-z) + z²+zx +x² /(y-z)(y-x) + x²+xy+ y²/ (z-x)(z-y)​

Answers

Answered by poojithashankar2008
2

Answer:

+ y z + z ² / ( x - y ) ( x - z ) + z ² + z x + z ² / ( y - 2 ) ( y - x ) + x ² + xy + y ² / ( z - x ) ( z - y )

your correct answer is 0

Similar questions