Math, asked by suddalaramu72, 4 months ago

y²dx+(x²-xy-y²)dy=0 non exact

Answers

Answered by promahri
0

y^2dx+(x^2-xy-y^2) dy=0

or, (x^2-xy-y^2) dy=-y^2dx

or, dy/dx = - y^2/(x^2-xy-y^2)

I didn't get it the question.. Please post complete question

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